json_decode() expects parameter 1 to be string, array given?

Question

this is my data ,After Json_encode()

 Array
        (
            [{"customerId":"1","customer_name":"Jon_doe","amount":"12312312","billcode":"b1231","billname":"cashbilname","billcategorycode":"1234","billcategory":"utility","month":"May","year":"2015","txcode":"10","stationid":"152","station":"Coroom","operatorcode":"1200","operator":"jame","terminal":"ter12312","txdate":"12\/2\/2015","txtime":"12:21:22_PM"}] 
    => 
        )

now i want to decode it back ,by applying json_decode() it gives the following error

json_decode() expects parameter 1 to be string, array given

any idea sugestion what to do ?

How do you encode? It looks like you doing something wrong there. — Sirko
– Sirko, Commented Jun 25, 2015 at 12:22
You need to pass the first item of that array to json_decode; rather than the whole array. So, json_decode($array[0]) — d0ug7a5
– d0ug7a5, Commented Jun 25, 2015 at 12:24
The error message is your answer.Did you searched at google with that error message?You would get lots of result. — Shaiful Islam
– Shaiful Islam, Commented Jun 25, 2015 at 12:27
json_encode should give you a string in the first place, not the Array you showed, so there's definitely a problem there. Show your code and we might be able to help — Aioros
– Aioros, Commented Jun 25, 2015 at 12:27

Fabien · Accepted Answer · 2021-01-22 10:16:11Z

9

Your json must be in string, not in array

$json_string = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$json_array = json_decode($json_string);

$json_array : ['a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5];

If your json is in array you can do :

$json_string_in_array = ['{"a":1,"b":2,"c":3,"d":4,"e":5}'];
$json_array = json_decode($json_string_in_array[0]);

edited Jan 22, 2021 at 10:16

answered Jun 25, 2015 at 12:27

Fabien

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1 Comment

mparo_afridi Over a year ago

say undefined 0 index

BBBThunda · Accepted Answer · 2015-06-25 12:28:28Z

3

json_encode() returns a string, so I don't know how you can be getting an array out of it unless you are storing it in an array yourself like:

$json = [];
$json[] = json_encode($someArray);

Instead, just store it in a non-array variable:

$jsonString = json_encode($someArray);

Then you can decode it like this:

$decodedArray = json_decode($jsonString);

answered Jun 25, 2015 at 12:28

BBBThunda

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Comments

PHPJungle · Accepted Answer · 2015-06-25 12:27:21Z

0

$jsonstr = '[{"customerId":"1","customer_name":"Jon_doe","amount":"12312312","billcode":"b1231","billname":"cashbilname","billcategorycode":"1234","billcategory":"utility","month":"May","year":"2015","txcode":"10","stationid":"152","station":"Coroom","operatorcode":"1200","operator":"jame","terminal":"ter12312","txdate":"12\/2\/2015","txtime":"12:21:22_PM"}]';
$ar = json_decode($jsonstr,true); # json string to Array
$obj = json_decode($jsonstr); # json string to Object
var_dump($ar,$obj);

answered Jun 25, 2015 at 12:27

PHPJungle

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