Mapping views.py in Django (Python)

Question

I need some help mapping views in Django. My app is pretty simple -- it's just a status page listing all of our environments and their corresponding apps. So far I have all the env's listed like so:

ENV_1
ENV_2
ENV_3

But what I want is: (where [app*] would be from app_list in my Environment class -- see below)

ENV_1  [app1] [app2] [app3] ...
ENV_2  [app1] [app2] [app3] ...
ENV_3  [app1] [app2] [app3] ...

Here's my models.py (app_list = app1, app2, etc.)

- - UPDATE - -

from django.db import models

class Environment(models.Model):
    name = models.CharField(max_length=128, unique=True)
    app_list = models.CharField(max_length=128, blank=True)

    def __str__(self):
        return self.name

    def format(self):
        app_list = self.app_list or ""
        return (" ".join(["[%s] " % a for a in app_list.split(',')]))

And my views.py:

from django.shortcuts import render
from dashboard.models import Environment, Page

def index(request):
    environment_list = Environment.objects.order_by('name')
    context_dict = {'environments': environment_list}

    for environment in environment_list:
        environment.url = environment.name.replace(' ', '_')

    return render(request, 'dashboard/index.html', context_dict)

def environment(request, environment_name_url):
    environment_name = environment_name_url.replace('_', ' ')
    context_dict = {'environment_name': environment_name}

    try:
        environment = Environment.objects.get(name=environment_name)
        context_dict['environment'] = environment
    except Environment.DoesNotExist:
        pass

    return render(request, 'dashboard/environment.html', context_dict)

And my index.html

<body>
  <h1>Title</h1>

  {% if environments %}
    td>
        {% for environment in environments %}
            <li><a href="/dashboard/environment/{{ environment.url }}">{{ environment.name }}</a>{{environment.format_apps_list}}</li>
    </td>
  {% else %}
    <strong>There are no environments present.</strong>
  {% endif %}

</body>

I want to loop through app_list and display them next to each env — syntax
– syntax, Commented Jul 14, 2015 at 14:54

Community · Accepted Answer · 2017-05-23 12:29:46Z

1

To fix your specific issue, you can do something like this:

class Environment(models.Model):
    name = models.CharField(max_length=128, unique=True)
    app_list = models.CharField(max_length=128, blank=True)

    def __str__(self):
        return self.name

    def format_apps_list(self):
        app_list = self.app_list or "" #if app_list is blank
        return (" ".join(["[%s] " % a for a in app_list.split(',')])

and you can call the format helper method in the template - feel free to modify it to your usecase.

{% for environment in environments %}
    <li><a href="/dashboard/environment/{{ environment.url }}">{{ environment.name }}</a> {{environment.format_apps_list}}</li>

I see a few things that could be changed in this app. I would also recommend using slugs - example this app is great (django-autoslug-field). One approach for this would be:

from django.db import models


class Environment(models.Model):
    name = models.CharField(max_length=128, unique=True)
    slug = AutoSlugField()

    def __str__(self):
        return self.name

class App(models.Model):
    environment = models.ForeignKey(Environment)
    name = models.CharField(max_length=128)
    slug = AutoSlugField()

This would give you the flexibility to analyze which apps are in an environment, and at the same time, what environments does an app belong to.

Your template would be

{% for environment in environments %}
    {% for app in environment.app_set.all %}
        {{app.name}}
    {% endfor %}
{% endfor %}

Also, now you can process the url by slug, instead of the name - which would eliminate all the .replace(..) hacks

edited May 23, 2017 at 12:29

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answered Jul 14, 2015 at 15:02

karthikr

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8 Comments

Bun Over a year ago

Does AutoSlugField() generate slug for each field? I normally use models.SlugField().

karthikr Over a year ago

That should be sufficient, but AutoSlugField does a little more - you can set it up for updating the slug when name changes, etc..

syntax Over a year ago

Thanks karthikr! Please forgive me for prying, but how could I implement the first part? Maybe add this to my views? application_list = format(app_list) and update: context_dict = {'environments': environment_list, 'applications': application_list}

karthikr Over a year ago

Check the edit. You can do it in the template directly.

syntax Over a year ago

Ugh I can't get {{environment.format.apps_list}} to return anything. I've even tried just returning self.name from that def and I still don't get anything. Thanks again... appreciate your patience.

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