Django - Url to dynamic model loading

Question

So I'm trying to load a model dynamically as such :

urls.py

url(r'^list_view/([\w-]+)$', Generic_list.as_view()),

Here's my Generic_list class in views.py :

class Generic_list(ListView):
    import importlib
    module_name = 'models'
    class_name = ?
    module = __import__(module_name, globals(), locals(), class_name)
    model = getattr(module, class_name)
    template_name = 'django_test/generic_list.html'

About security, later I'll only allow classes from a white list.

So, what can I put in place of the question mark in order to get the class name from the url?

Hi there, have a look at this ccbv.co.uk/projects/Django/1.8/django.views.generic.list/… — Paco
– Paco, Commented Jul 17, 2015 at 11:05

Community · Accepted Answer · 2017-05-23 12:29:47Z

1

If you want to have your model loaded dynamically, you could do something like this:

class Generic_list(ListView):
    template_name = 'django_test/generic_list.html'

    @property
    def model(self):
        return # code that returns the actual model

More information about property. Basically, it will understand this method as an attribute of the class. Instead of having to define this attribute at the class level (meaning that the code will be evaluated when the file is imported by django), you make it look like it is an attribute, but it's acting like a method, allowing you to add business logic.

edited May 23, 2017 at 12:29

CommunityBot

11 silver badge

answered Jul 17, 2015 at 11:06

Paco

4,7263 gold badges31 silver badges54 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Ernest · Accepted Answer · 2015-07-17 11:17:52Z

1

You could try to use property decorator and get_model method:

from django.views.generic import ListView
from django.apps import apps


class GenericList(ListView):

    @property
    def model(self):
        # Obtain model name here and pass it to `get_model` below.
        return apps.get_model(app_label='app_label', model_name='model_name')

Also, consider reading PEP 0008 for naming conventions.

answered Jul 17, 2015 at 11:17

Ernest

2,9691 gold badge14 silver badges29 bronze badges

Collectives™ on Stack Overflow

Django - Url to dynamic model loading

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related