Convert 2D array into object array

Question

I've got a 2D array and I need to convert each "line" of the array into a separate object array element that contains a String, an Int and multiple Doubles. Right now each 2D array element is stored as a String.

Here is my class object:

public Object() {
    String = "null";
    Double1 = -1.0;
    Double2 = -1.0;
    Double3 = -1.0;
    Integer = -1; 
}

Here is my method used to convert the 2D array to a class array:

 public static void objectConvert() {
        Object[] objArray = new Object[count];
        for (int i = 0; i<count; i++) {
            objArray[i] = new Object(data[i][0], Double.parseDouble(data[i][1]), Double.parseDouble(data[i][2]), Double.parseDouble(data[i][3]), Integer.parseInt(data[i][4]));
        }
        System.out.println(objArray[0]);
        System.out.println(objArray[1]);
    }

Here are the error that I get when compiling:

 javac Program.java

Program.java:42: error: constructor Object in class Object cannot be applied to given types;
                        Object[i] = new Object(data[i][0],
 Double.parseDouble(data[i][1]), Double.parseDouble(data[i][2]), Double.parseDouble(data[i][3]), Integer.parseInt(data[i][4]));
                                               ^
  required: no arguments
  found: String,double,double,double,int
  reason: actual and formal argument lists differ in length
1 error

Don't define a class named Object or any other predefined class. You will end up confusing yourself and other programmers. — Codebender
– Codebender, Commented Jul 31, 2015 at 4:19

Ram Patra · Accepted Answer · 2015-07-31 04:20:02Z

1

Use objArray[i] in place of Object[i] while assigning inside the for loop.

There is one more error, you haven't defined a constructor which takes String,double,double,double,int and consider renaming your class from Object to something else.

Your constructor can be like this:

public Object(String a, Double b, Double c, Double d, Integer e) {
    string = a;
    double1 = b;
    double2 = b;
    double3 = d;
    integer = e; 
}

edited Jul 31, 2015 at 4:20

answered Jul 31, 2015 at 4:13

Ram Patra

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2 Comments

Ram Patra Over a year ago

@user3264252 I guess you are new to java, please follow camel case while naming your variables.

user3264252 Over a year ago

I changed it to Object just to make it easier to understand as my actual variables are named confusingly to an outsider

Dileep · Accepted Answer · 2015-07-31 04:15:57Z

0

Object[i] = new Object(data[i][0], Double.parseDouble(data[i][1]), Double.parseDouble(data[i][2]), Double.parseDouble(data[i][3]), Integer.parseInt(data[i][4]));

its

objArray[i]=  new Object(data[i][0], Double.parseDouble(data[i][1]), Double.parseDouble(data[i][2]), Double.parseDouble(data[i][3]), Integer.parseInt(data[i][4]));

Your class Object must have a constructor that have reads 5 parameter (String, double, double, double, Integer)

edited Jul 31, 2015 at 4:15

answered Jul 31, 2015 at 4:11

Dileep

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2 Comments

user3264252 Over a year ago

Ooh thank you, that fixed that mistake, but I'm still getting the other error: Program.java:42: error: constructor Object in class Object cannot be applied to given types; Object[i] = new Object(data[i][0], Double.parseDouble(data[i][1]), Double.parseDouble(data[i][2]), Double.parseDouble(data[i][3]), Integer.parseInt(data[i][4])); ^ required: no arguments found: String,double,double,double,int reason: actual and formal argument lists differ in length

Dileep Over a year ago

possibly because of the absence of the constructor.

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