Converting NSArray to NSMutableArray [closed]

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As above. Would be helpful to know. Thanks!

adding "need this urgently" is likely to have the opposite effect... — Mitch Wheat
– Mitch Wheat, Commented Jul 11, 2010 at 6:40
This is like the third exact question on NSArray and NSMutableArray's today. — Anurag
– Anurag, Commented Jul 11, 2010 at 7:10

Cameron Spickert · Accepted Answer · 2011-09-02 18:26:10Z

85

Here are two options:

- (NSMutableArray *)createMutableArray1:(NSArray *)array
{
    return [NSMutableArray arrayWithArray:array];
}

- (NSMutableArray *)createMutableArray2:(NSArray *)array
{
    return [[array mutableCopy] autorelease];
}

answered Sep 2, 2011 at 18:26

Cameron Spickert

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1 Comment

Nick N Over a year ago

Here's a conversion back to an NSArray: NSArray *array = [NSArray arrayWithArray:mutableArray];

Fabian Kreiser · Accepted Answer · 2013-02-11 12:11:41Z

18

Use -mutableCopy and make sure to balance the retain count.

NSMutableArray *mutableArray = [[immutableArray mutableCopy] autorelease];

edited Feb 11, 2013 at 12:11

answered Sep 2, 2011 at 18:22

Fabian Kreiser

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2 Comments

Marcel Marino Over a year ago

It's now: NSMutableArray *mutableArray = [immutableArray mutableCopy];

falkon21 Over a year ago

@MarcelMarino That's correct!

SSteve · Accepted Answer · 2014-04-28 23:44:23Z

11

Try this one

NSMutableArray *array = [[NSMutableArray alloc]initWithArray:your_array_name];

edited Apr 28, 2014 at 23:44

SSteve

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answered Feb 12, 2013 at 9:00

dhaya

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