How do I encode Character using NSCoder in swift?

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How do I encode enum using NSCoder in swift?

Code:

import Foundation

class Car: NSObject, NSCoding {
    var bmw: Character
    required init(coder decoder: NSCoder) {
        bmw = (decoder.decodeObjectForKey("bmw") as? Character)!
    }

    func encodeWithCoder(encoder: NSCoder) {
        encoder.encodeObject(bmw, forKey: "bmw")
    }
}

Xcode throw an error:

Cannot invoke 'encodeObject' with an argument list of type '(Characher, forKey: String)'

What should I do with Character in swift?

Renzo · Accepted Answer · 2015-08-27 08:16:35Z

1

The reason of the error is that, while String is subtype of AnyObject, Character is not (since a character is not an object). A way to solve your problem could be the following:

class Car: NSObject {
  var bmw: Character
  required init(coder decoder: NSCoder) {
    bmw = Character(decoder.decodeObjectForKey("bmw") as! String)
  }

  func encodeWithCoder(encoder: NSCoder) {
    encoder.encodeObject(String(bmw), forKey: "bmw")
  }
}

Here you convert the character to a string before encoding it, and convert back to character after decoding.

edited Aug 27, 2015 at 8:16

answered Aug 27, 2015 at 6:22

Renzo

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5 Comments

Zitong Over a year ago

Thank you! And I want to know Character(abc) and String(abc) wether cost a lot system resources. Beacuse I will have thousands of objects to deal with.

Renzo Over a year ago

I don't think these operations will cost too much, since they can be efficiently executed in O(1) time.

Zitong Over a year ago

And do you know other method to solve it without convert between character and string?

Renzo Over a year ago

Maybe you could change the representation of characters and use an Int instead, using encodeInt:forKey and decodeIntForKey, and then converting the integer to a character only when you need to print it?

Zitong Over a year ago

Thanks. I need a Character to be a key in my class, and all of characters are Chinese utf-8 characters. :-(

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