Turn user input string into mathematical function

Question

For the purposes of what I want to do I need to take a user input as a string and convert it into an unevaluated function. For example, if the user input was "x^2*sin(x)" I would need a function that took a double input x and returned

Math.Pow(x, 2)*Math.Sin(x)

I need the function, I can't pass in a value for x and I will be calling the function many times (hundreds possibly) so I can't parse the string each time I am making a calculation.

How would I implement this? I take it from the question Convert a string into mathematical equation? that there is not a standard way to do this. But I am a little lost as to how to "save" a mathematical formula, is there a way to create a delegate with the math expression?

At the very least, I need it to recognize basic algebra equations, powers, exponentials, and trig functions. Also, although I used the example of a function of a single variable x, I want to be able to parse a function of multiple variables.

I did Google the question as a comment in the linked question suggests, it led me back to Stack Overflow. — kleineg
– kleineg, Commented Sep 1, 2015 at 13:38
have you tried: c-sharpcorner.com/UploadFile/mgold/… or ncalc.codeplex.com? — avi
– avi, Commented Sep 1, 2015 at 13:46

Sergey Kolodiy · Accepted Answer · 2015-09-01 13:53:56Z

3

Essentially, you need to implement your own syntax parser and convert input string into an Expression Tree.

answered Sep 1, 2015 at 13:53

Sergey Kolodiy

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Comments

kleineg · Accepted Answer · 2015-09-03 14:44:46Z

I ended up using NCalc. I passed in the user's string expression, replaced the variables with the values I am evaluating at, then using the Evaluate method and parsing to a double.

private double Function(double t, double y)
    {
        NCalc.Expression expression = new NCalc.Expression(this.Expression);
        expression.Parameters["t"] = t;
        expression.Parameters["y"] = y;

        double value;

        double.TryParse(expression.Evaluate().ToString(), out value);

        return value;        
    }

For example, given the inputs t = .5 and y = 1 and the expression "4*y + Tan(2*t)", we would evaluate the string "4*1 + Tan(2*.5)" using NCalc.

It is not perfect, NCalc throws an exception if it cannot parse the user's string or it the datatypes of functions are different. I am working on polishing it.

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