jQuery basic ajax GET + php return

Question

EDIT: fixed _ typo (2x), added header, still logging 100.

Upon clicking a button in my JavaScript, I'm firing this function (parameter: 100)

ajaxManager = new AjaxManager();
ajaxManager.requestHexContent(100);

function AjaxManager (){
    this.requestHexContent = function(id){
        $.ajax({
            type : 'get',
            url : 'simulator/hexFiller.php',
            dataType : 'json',
            data: {
                gameid: id,
            },
            success : function(ret){
                console.log(ret);
            },
            error : function(){
                alert("error")
            }
        });
    },
}

this is my hexFiller.php

<?php   
header('Content-Type: application/json');

  $ret; 

  if (isset($_GET["gameid"])){
    if ($_GET["gameid"] == 100){
        $ret = 200;
    }
   else {
    $ret = "error";
 }
}

echo json_encode($ret);

?>

Now, what i would expect to happen is for my browser to log "200" to the console, or, "error". Instead it logs "100" to the console.

Can someone explain to me the fundamental error in my thinking?

How are you calling the function? Can we have the code when you fire this function upon clicking? — Ashish Choudhary
– Ashish Choudhary, Commented Oct 15, 2015 at 17:18
edited the code, also added in the call of requestHexContent() — C. Finke
– C. Finke, Commented Oct 15, 2015 at 17:21
Its working perfectly fine here. Earlier it was coming under error and alerted "error". When I changed $GET into $_GET. It returned 200. Anything else you wanted? Shall I paste the code? — Ashish Choudhary
– Ashish Choudhary, Commented Oct 15, 2015 at 17:28
mh. Perhaps something different is wrong with secureWAMP then. thanks for investigating. — C. Finke
– C. Finke, Commented Oct 15, 2015 at 17:29

Ashish Choudhary · Accepted Answer · 2015-10-15 17:36:54Z

As discussed in the comment, working code is mentioned below: I only replaced $GET with $_GET.

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
    function AjaxManager() {
        this.requestHexContent = function (id) {
            $.ajax({
                type: 'get',
                url: 'simulator/hexFiller.php',
                dataType: 'json',
                data: {
                    gameid: id,
                },
                success: function (ret) {
                    console.log(ret);
                },
                error: function () {
                    alert("error")
                }
            });
        }
    }

    ajaxManager = new AjaxManager();
    ajaxManager.requestHexContent(100);
</script>

hexFiller.php

<?php
$ret;

if (isset($_GET["gameid"])) {
    if ($_GET["gameid"] == 100) {
        $ret = 200;
    } else {
        $ret = "error";
    }
}

echo json_encode($ret);
?>

BurningLights · Accepted Answer · 2015-10-15 16:57:44Z

0

You have a slight error in your PHP code. You're trying to use $GET[] to get parameters passed to the PHP script. But, it's $_GET[] that you need to use. See http://php.net/manual/en/reserved.variables.get.php.

answered Oct 15, 2015 at 16:57

BurningLights

2,4071 gold badge17 silver badges22 bronze badges

1 Comment

Sandeep Nayak Over a year ago

But why does it log 100?

wayzz · Accepted Answer · 2015-10-15 16:58:59Z

0

You are not returning a json element from your PHP file.

Add header('Content-Type: application/json'); at the top of your PHP file.

Also your $_GET declaration is incorrect.

answered Oct 15, 2015 at 16:58

wayzz

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Comments

Vitor Paiva · Accepted Answer · 2015-10-15 17:02:57Z

0

Why it is returning 100, I don't really know, probably an error number. But your PHP code is wrong, it's $_GET not $GET.

answered Oct 15, 2015 at 17:02

Vitor Paiva

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