How to get exit status from a Java program in a batch file

Question

I'm newbie in batch programming (I don't know much about batch files). My boss has asked me to write a batch file that runs a Java application. The batch file has something like this:

echo ロックテーブル削除

java -cp n:\kanesin.root\bin\Sys.Boundary.BatchMain.jar /JobID:BCM0020  
if not ERRORLEVEL 0 (
    echo Teiji_H01.bat BCM0020 > rerun.bat
    goto ERROREXIT
)

but I don't know how the Java application sends the ERRORLEVEL to this batch file. Do I have to return an integer value, or use System.exit(number); ?

Wyzard · Accepted Answer · 2015-10-16 04:58:18Z

3

Do I have to return an integer value, or use System.exit(number); ?

Yes. You set that by using System.exit(int) which (per the Javadoc)

Terminates the currently running Java Virtual Machine. The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination.

edited Oct 16, 2015 at 4:58

Wyzard

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answered Oct 16, 2015 at 4:33

Elliott Frisch

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