iOS - Swift - Loop for with array and condition

Question

I'm looking for doing a loop on an array but want to stop after a condition. This is what I have now (btw, I'm using Parse as back-end).

let query = PFQuery(className: "MyObject")
query.whereKey("user", equalTo: PFUser.currentUser())
query.findObjectsInBackgroundWithBlock { (objects:[AnyObject]!, error:NSError!) -> Void in
        if error == nil {
            for object in objects {
                print(object.objectId)
            }
        }
}

This code is printing every objectId.

Now let's imagine I want to print every object until my find an object with objectId == "xxx".

How should I do that?

you can return or break out of the loop. if objectId == "xxx" { break/return } — Adrian
– Adrian, Commented Oct 28, 2015 at 15:10
Does Swift not have the concept of break? That's the standard method of escaping from a loop in most languages. — GordonM
– GordonM, Commented Oct 28, 2015 at 15:12

katleta3000 · Accepted Answer · 2015-10-28 15:41:37Z

4

If you want to filter objId and perform some code:

let array = ["id1", "id2", "id3", "id4"]
for objId in array where objId != "id3" {
    print(objId)
}

answered Oct 28, 2015 at 15:41

katleta3000

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Comments

Arsen · Accepted Answer · 2015-10-28 15:45:17Z

3

I think filter is what you're looking for

let objects = [["id": 1], ["id": 2], ["id": 3]]
objects.filter { $0["id"] != 3 }.forEach { print($0) }

edited Oct 28, 2015 at 15:45

answered Oct 28, 2015 at 15:32

Arsen

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Comments

Anbu.Karthik · Accepted Answer · 2015-10-28 15:10:27Z

2

try this

 for object in objects {
            print(object.objectId)

      if object.objectId == "xxx"
       {
         // object Name is found
         // if you like to break the execution use "break"
         //break
        }
       else
        {
          // object ID not found
        }
      }

answered Oct 28, 2015 at 15:10

Anbu.Karthik

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