YII2 Custom validation is not working with custom function model rule

Question

I am trying to implement with custom function in model its not working i am not getting what's wrong in my code. i am trying to call with basic later i will put my condition.

Here is model code

public function rules()
    {
        return [
            ['mobile_number', 'required'],
            ['mobile_number', 'myfunction'],

        ];
    }

public function myfunction($attribute,$params)
    {
             $this->addError($attribute, 'You have already submitted');

    }

Here is controller code

public function actionCreate()
    {
        $model = new Createuser();

        if ($model->load(Yii::$app->request->post()) && $model->save()) {
            return $this->redirect(['view', 'id' => $model->id]);
        } else {
            return $this->render('create', [
                'model' => $model,
            ]);
        }
    }

its not assiging the error to a form-field.

Thanks in advance.

I'm having the same problem in my application, did you solved it? Have any ideas? — Clyff
– Clyff, Commented Feb 5, 2016 at 13:19

Baron Lam · Accepted Answer · 2020-03-08 12:09:21Z

3

I guess the parameter named mobile_number does not exist in your data or it is an empty string, so try to add 'skipOnEmpty' => false in your code.

Anyway, it works for me.

public function rules()
{
    return [
        ['mobile_number', 'required', 'skipOnEmpty' => false],
        ['mobile_number', 'myfunction', 'skipOnEmpty' => false],
    ];
}

edited Mar 8, 2020 at 12:09

answered May 17, 2019 at 9:17

Baron Lam

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Comments

thepiyush13 · Accepted Answer · 2015-12-03 07:20:43Z

0

are you sure you are not extending the model class ? if so you need to put this :

$model->validate()

answered Dec 3, 2015 at 7:20

thepiyush13

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Comments

vishuB · Accepted Answer · 2015-12-03 07:31:28Z

0

Your Model:

public function rules()
{
    return [
        ['mobile_number', 'required'],
        ['mobile_number', 'myfunction'],
    ];
}

public function myfunction($attribute,$params)
{
    $this->addError($attribute, 'You have already submitted');
    return false;   
}

And your controller:

public function actionCreate()
{
    $model = new Createuser();

    if ($model->load(Yii::$app->request->post()) && $model->save() && $model->validate()) {
        return $this->redirect(['view', 'id' => $model->id]);
    } else {
        return $this->render('create', [
            'model' => $model,
        ]);
    }
}

answered Dec 3, 2015 at 7:31

vishuB

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2 Comments

vishuB Over a year ago

please enter first mobile number and then submit form then you can show error msg

Santosh Over a year ago

i need to show while submitting to a form-field in this form also reseting. and pjax is not working.

Amitesh Kumar · Accepted Answer · 2015-12-03 10:15:18Z

0

try this in your controller

protected function performAjaxValidation($model = NULL) {

        if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
            Yii::$app->response->format = Response::FORMAT_JSON;
            echo json_encode(ActiveForm::validate($model));
            Yii::$app->end();
        }
    }

public function actionCreate()
{
    $model = new Createuser();
    $this->performAjaxValidation($model);
    if ($model->load(Yii::$app->request->post()) && $model->save() && $model->validate()) {
        return $this->redirect(['view', 'id' => $model->id]);
    } else {
        return $this->render('create', [
            'model' => $model,
        ]);
    }
}

answered Dec 3, 2015 at 10:15

Amitesh Kumar

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Comments

Santosh · Accepted Answer · 2017-06-08 11:20:59Z

0

Code is fine. it was error with Dynamic Form validation.

answered Jun 8, 2017 at 11:20

Santosh

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