How to generate 3 random values from an array

Question

I have written a method which works to generate one random value of an array, but I don't know how to generate the other two because they all end up just being the same number. Here is what I have written, but it just crashes...

public void getRandomTopics() {
Random random = new Random();

int index = random.nextInt(group_topics.length);

randomOne = group_topics[index];
randomTwo = group_topics[index];
randomThree = group_topics[index];

if(randomOne.equals(randomTwo) || randomOne.equals(randomThree) || randomThree.equals(randomTwo)) {
    isEqual = true;
}
while(isEqual = true){
    randomOne = group_topics[index];
    randomTwo = group_topics[index];
    randomThree = group_topics[index];

}
topicOne = (TextView) findViewById(R.id.textView2);
topicOne.setText(randomOne);

topicTwo = (TextView) findViewById(R.id.textView3);
topicTwo.setText(randomTwo);

topicThree = (TextView) findViewById(R.id.textView4);
topicThree.setText(randomThree);

}

If anyone knows an easier way to do this help is greatly appreciated:)

You need to create random numbers 3 times and not 1 time only. — Atri
– Atri, Commented Feb 17, 2016 at 3:47
Well, since all 3 are extracted in parallel using group_topics[index], without changing the value of index in between, why would you expect different values? — Andreas
– Andreas, Commented Feb 17, 2016 at 3:47

Atri · Accepted Answer · 2016-02-17 03:49:07Z

1

Create 3 different random numbers:

int index1 = random.nextInt(group_topics.length);
int index2 = random.nextInt(group_topics.length);
int index3 = random.nextInt(group_topics.length);

Now use these 3 random numbers instead of the same index that you generate only once.

randomOne = group_topics[index1];
randomTwo = group_topics[index2];
randomThree = group_topics[index3];

answered Feb 17, 2016 at 3:49

Atri

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