Populate another input field value after first input value

Question

I have two scripts....

1. HTML Part :

<html>
<head>
<script src="//code.jquery.com/jquery-1.9.1.js"></script> 

<script>

function loaddata()
{

var email=document.getElementById( "email" );
var email1 =  $(email).val();
if(email1)
{
$.ajax({
        type: 'post',
        url: 'form-inputs.php',
        data: {
        user_email:email1,
        },
        success: function (response) {

        // We get the element having id of display_info and put the response inside it
        $( '#display_info' ).html(response);

        }
       });

    }

else
{
$( '#display_info' ).value("Please Enter Some Words");
}

}

</script>

</head>
<body>
<input name="email" id="email"  onkeyup="loaddata();" required/>

<br><br>
<input name="udf1" id="udf1"  readonly="readonly"/>

<br>
 <div id="display_info" ></div>
</body>
</html>

2. form-inputs.php :

<?php
$con = mysql_connect("localhost","username","password");
if (!$con)
{
die("Could not connect: " . mysql_error());
}
mysql_select_db("databasename", $con);
##############################

if( isset( $_POST['user_email'] ) ){

$emailfetch=$_POST['user_email'];

$sqlraw = "select username, email from registration where email = '$emailfetch' ";

$sql=mysql_query($sqlraw);

while($row=mysql_fetch_array($sql)){

    if(isset($row['email'])){
      echo $row['username']; //shown only if post email exists in database
    }else{
    echo "Check Email Again";
    }
  }
}
?>

With these codes, I am getting username shown properly in div with id display_info. .

But I want to use and set this username value in my second udf1 input field.

Help appreciated.

Can't get clearly what you actually want. Can you elaborate it? — Jyothi Babu Araja
– Jyothi Babu Araja, Commented Feb 20, 2016 at 5:41
@JyothiBabuAraja I am getting username displayed in div with id display_info.. I want to display username in input field udf1 as value... — Dr M L M J
– Dr M L M J, Commented Feb 20, 2016 at 5:43

Jyothi Babu Araja · Accepted Answer · 2016-02-20 05:48:23Z

2

Use this

echo '<input type="text" name="user" value="' . $row['username'] . '">';

instaead of this

echo $row['username']; //shown only if post email exists in database

answered Feb 20, 2016 at 5:48

Jyothi Babu Araja

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Comments

Ashish · Accepted Answer · 2016-02-20 05:51:54Z

1

Have you tried this?

$('#udf1').val(response);

after

$( '#display_info' ).html(response);

May be this can help.

answered Feb 20, 2016 at 5:51

Ashish

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