Java Translate XML into HTML using XSL

Question

I used JAXB to create a very complicated .xml file which I saved on the drive. I also manually made an .xsl file which is my template.

How do I now programmatically use the above two to create an html output file ?

I tried various things and maybe I'm just tired but I can't even successfully open the .xml file into a Document.

Does someone have a working example ? I would greatly appreciate it! Thanks :)

I tried various things, including the official code examples but I can't find a working example. Nothing but null pointer exceptions. :(

Did you come across any performance issue ? I have the same kind of code and now I see some performance hit in PROD. — Hardik Mishra
– Hardik Mishra, Commented Sep 13, 2017 at 17:39

Spotted · Accepted Answer · 2016-02-29 09:58:27Z

4

The smallest working example I can give you:

import java.io.File;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class UseXMLToHTML {

    public static void main(String[] args) throws TransformerException {
        StreamResult result = new StreamResult(new File("output.html"));
        StreamSource source = new StreamSource(new File("input.xml"));
        StreamSource xslt = new StreamSource(new File("transform.xslt"));

        Transformer transformer = TransformerFactory.newInstance().newTransformer(xslt);

        transformer.transform(source, result);
    }
}

answered Feb 29, 2016 at 9:58

Spotted

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2 Comments

codeCompiler77 Over a year ago

Thanks a lot mate, this helped me a great deal. =D

Hardik Mishra Over a year ago

In PROD, I am seeing some Thread getting stuck issues. Any pointers. stackoverflow.com/questions/46194800/…

mschr · Accepted Answer · 2016-02-29 09:58:36Z

2

This would probably do the trick;

import javax.xml.transform.*;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import java.io.File;
import java.io.IOException;
import java.net.URISyntaxException;

public class TestMain {
    public static void main(String[] args) throws IOException, URISyntaxException, TransformerException {
        TransformerFactory factory = TransformerFactory.newInstance();
        Source xslt = new StreamSource(new File("transform.xslt"));
        Transformer transformer = factory.newTransformer(xslt);

        Source text = new StreamSource(new File("input.xml"));
        transformer.transform(text, new StreamResult(new File("output.xml")));
    }
}

Consider trying out stuff from these urls:

http://www.w3schools.com/xsl/tryxslt.asp?xmlfile=cdcatalog&xsltfile=cdcatalog

http://www.w3schools.com/xsl/tryxslt_result.asp?xmlfile=cdcatalog&xsltfile=cdcatalog

answered Feb 29, 2016 at 9:58

mschr

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1 Comment

codeCompiler77 Over a year ago

Thank you good sir, not sure which of you posted first but i appreciate the help, i got it working :) Sort off! Lots to do!

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