var str = "test test1 test2 test3";
Any way to grab "test test1" and "test2 test3"? (anything before the second space and anything after second space)
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1Two possible approaches: regex; splitting the string at spaces and then rebuilding the components you need.Andre M– Andre M2016-03-31 19:50:39 +00:00Commented Mar 31, 2016 at 19:50
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4What you've tried so far?Victor– Victor2016-03-31 19:51:20 +00:00Commented Mar 31, 2016 at 19:51
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3 Answers
Assuming you know the string has at least two spaces:
var str = "test test1 test2 test3";
var index = str.indexOf( ' ', str.indexOf( ' ' ) + 1 );
var firstChunk = str.substr( 0, index );
var secondChunk = str.substr( index + 1 );
If you're unsure:
var str = "test test1 test2 test3";
var index = str.indexOf( ' ', str.indexOf( ' ' ) + 1 );
var firstChunk = index >= 0 ? str.substr( 0, index ) : str.substr( index + 1 );
if ( index >= 0 )
var secondChunk = str.substr( index + 1 );
1 Comment
RRR
Hi you code works fine thanks... but if there is a leading space how to get the 1st 2 words and next 2 words? in other words how to do this for 3space? any help is appreciated :)
Using split and some array's functions
var str = "test test1 test2 test3";
var n = 2; // second space
var a = str.split(' ')
var first = a.slice(0, n).join(' ')
var second = a.slice(n).join(' ');
document.write(first + '<br>');
document.write(second);
Comments
Regexp alternative:
var str = "test test1 test2 test3",
parts = str.match(/^(\S+? \S+?) ([\s\S]+?)$/);
console.log(parts.slice(1,3)); // ["test test1", "test2 test3"]
