Efficient way to filter array of Person objects based on an array of string names

Question

I have an array of names:

var namesArray = ["Bert","Tony","Phil","George", "David"]

I then have an array of Person Objects:

var personsArray: [Person]

And a snippet of my Person class is:

class Person {
    var name: String

 ...some code omitted...
}

I am looking for a way to filter my array of Persons objects to only include the Person whos name is found in the namesArray.

I considered using the .filter on the array but I need to loop over two arrays.

 let filterByNameArray =  persons.filter({
    ($0.name == //string)!
  })

But I believe this is incorrect as I need to loop through the names array also. I solved my issue using a double for loop:

 var pArray: [Person] = []

  for person in personsArray {

    for nameString in namesArray {
      if person.name == nameString {
        pArray.append(person)
      }
    }
  }

However, this is ugly and uses a significant amount of CPU so my question is,is there a more efficient way to do this? :) Im sure there is.

@TimVermeulen no problem, I subclass NSObject so I can compare one Person object to another. — DevC
– DevC, Commented May 5, 2016 at 15:33
@TimVermeulen thanks for the tip. Im just beginning Swift at the moment so I have plenty to learn. :) — DevC
– DevC, Commented May 5, 2016 at 15:36

Price Ringo · Accepted Answer · 2016-05-05 15:23:05Z

1

Use the contains method on the namesArray to search all of it.

let filteredByNameArray = persons.filter {
  namesArray.contains($0.name)
}

answered May 5, 2016 at 15:23

Price Ringo

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