const array = ["item 1", "item 2", "item 3", "item 4"];
// removes the first element of the array, and returns that element.
console.log(array.shift());
// prints "item 1"
//removes the last element of the array, and returns that element.
console.log(array.pop());
// prints "item 4"How to remove the first array but return the array minus the first element?
In my example I should get "item 2", "item 3", "item 4" when I remove the first element?
The .shift() method removes the first element of an array. Then you can return the remaining:
const array = ["item 1", "item 2", "item 3", "item 4"];
array.shift();
console.log(array);As others have suggested, you could also use slice(1):
const array = ["item 1", "item 2", "item 3", "item 4"];
console.log(array.slice(1));
slice(1) doesn't "remove the first element" from the array. Instead, it creates a new array with shallow copies of all of the values from the array except the first.
Why not use ES6?
const array = ["item 1", "item 2", "item 3", "item 4"];
const [, ...rest] = array;
console.log(rest)
const [,...rest] = myarray =O =D
Try this:
const array = ["item 1", "item 2", "item 3", "item 4"];
// removes the first element of the array, and returns that element apart from item 1.
array.shift();
console.log(array);
"item 1"Use:
array.slice(1, array.length);
as follows:
const array = [1, 2, 3, 4, 5, 6, 7, 8, 9];
const array2 = array.slice(1, array.length); //arrayExceptfirstValue
console.log(array2);myarray.splice(1) will remove the first item from the array … and return the updated array (['item 2', 'item 3', 'item 4'] in your example).
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice
This can be done in one line with lodash _.tail:
const array = ["item 1", "item 2", "item 3", "item 4"];
console.log(_.tail(array));<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>The easiest way I can think of is this:
const array = ["item 1", "item 2", "item 3", "item 4"];
const [, ...arrayYouNeed] = array;
console.log(arrayYouNeed);The original array is untouched and you can use the arrayYouNeed wherever you need it.
If you wanna know how it works look up 'deconstructing arrays'!
If you do not want to modify the array, you can either slice or filter out by index.
const array = [1, 2, 3, 4];
console.log(array.filter((_, i) => i !== 0));
console.log(array.slice(1));
console.log(array);Just for fun :)
We can create our function to remove at any index and get rest array:
const array = ["item 1", "item 2", "item 3", "item 4"];
const removeNthElement = (removeIndex, arr) => {
if (removeIndex < 0 || removeIndex >= array.length) return [...arr];
const result = Array(arr.length - 1);
for (let i = 0; i < removeIndex; ++i) {
result[i] = arr[i];
}
for (let i = removeIndex + 1; i < arr.length; ++i) {
result[i - 1] = arr[i];
}
return result;
}
// Testing
for (let i = -1; i <= array.length; ++i) {
console.log(removeNthElement(i, array));
}You can use array.slice(0,1) // First index is removed and array is returned.
alert(array.slice(1))orarray.shift(); alert(array);myarray.shift()returns"item 1"what i want is return"item 2", "item 3", "item 4"shift()[,...myarray] = myarray;