Replace nth occurrence javascript

Question

in this example string '1,2,3,4,5' I am trying to capture and replace the 3rd occurence of the comma , character

this code here

'1,2,3,4,5'.match(/(?:[^,]*,){2}[^,]*(,)/)

matches 1,2,3 and the comma im looking for but not sure how to replace just the comma

'1,2,3,4,5'.replace(/(?:[^,]*,){2}[^,]*(,)/, "$")

replaces everything before 4 giving $4,5

i just want a string result like 1,2,3$4,5 for example

I have achieved this task in two different ways, with array split and slice and with a String#replace that takes a callback

//splice
let parts = [];
let str = "1,2,3,4,5"; 
let formatted = ((parts = str.split(",")).slice(0,3)).join("-") + ' ' + parts.slice(3).join(":")

//callback
let str = "1,2,3,4,5"; 
str.replace(/,/g, (() => {
  let count = 0;
  return (match, position) => {
    count += 1;
    if(count == 3) return ' ';
    else if(count < 3) return '-';
    else return ':';        
  });
})())

Is this even possible with a plain String#replace?

Tushar · Accepted Answer · 2016-07-20 08:45:23Z

2

You can use capturing group and replace by first capturing group

.replace(/((?:[^,]*,){2}[^,]*),/g, "$1:");
          ^                  ^

The captured group will capture the matched string except the third comma which is $1 in the replacement string.

console.log('1,2,3,4,5,2,3,4,5,2,3,4,5'.replace(/((?:[^,]*,){2}[^,]*),/g, "$1:"));

answered Jul 20, 2016 at 8:45

Tushar

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