How to sum two different functions in javascript [duplicate]

Question

I have different functions which return values; So i created different function to sum both values.

function result(){
    var result = firstFunct() + secondFunct();
    alert(result);
    return result;
}

And it gives for me a result like joint of two strings: 1010 instead 20. What kind of operator do I need to use two sum both of them?

Make sure you return numbers from those functions, not strings, and don't return the alert() function, but the result. — adeneo
– adeneo, Commented Jul 23, 2016 at 20:44
Note also that it is confusing to have a variable (result) with the same name as the function. — Raymond Chen
– Raymond Chen, Commented Jul 23, 2016 at 20:46

Mursaleen Ahmad · Accepted Answer · 2016-07-25 16:09:09Z

3

This is most probably because your functions are returning string and not a numeric data type. You will need to cast the output of the functions

var result = Number(firstFunct()) + Number(secondFunct());

Note, casting to a number could also be done in a shorter way, using the + operator:

var result = (+firstFunct()) + (+secondFunct());

edited Jul 25, 2016 at 16:09

user663031

answered Jul 23, 2016 at 20:41

Mursaleen Ahmad

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3 Comments

MrVitaminasG Over a year ago

Thanks, it works... I been suspicious it is a string. Thanks again!

Mursaleen Ahmad Over a year ago

@MrVitaminasG - could you accept this answer?

MrVitaminasG Over a year ago

I was waiting for countdown to vote. The system not giving to vote straight away

Thevs · Accepted Answer · 2016-07-24 08:14:23Z

0

To cast to a numeric you can also do:

var num = 1 * numericstring;

answered Jul 24, 2016 at 8:14

Thevs

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4 Comments

user663031 Over a year ago

Well, +numericString is probably preferable.

Thevs Over a year ago

This can be mistreated as concatenation.

user663031 Over a year ago

Mistreated by whom, in what way? The unary plus has exactly one meaning, According to the documentation, "The unary plus operator precedes its operand and evaluates to its operand but attempts to converts it into a number, if it isn't already."

Thevs Over a year ago

I mean syntactic constructs like a + (+b) and even a++b are ugly and prone for errors. These cannot be used in expressions as easily and clearly as 1*a + 1*b.

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