1

Say I have this function...

public getStuff(): Observable<Stuff> {
     return.http.get('url')
          .map(res => res.json())
          .map((data: Piece) => {
               var stuff = new Stuff();
               // Apply logic to "data", modify stuff model, return stuff to subscriber
          });
}

How do I return the stuff object to the observer instead of the "data" of type Piece?

1
  • 2
    Doesn't return stuff; inside that second map function do what you ask? If not, how is it different? Commented Aug 2, 2016 at 5:26

1 Answer 1

3

If you use a code block you need an explicit return:

public getStuff(): Observable<Stuff> {
     return.http.get('url')
          .map(res => res.json())
          .map((data: Piece) => {
               var stuff = new Stuff();
               return stuff;
          });
}
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