Map Dynamic json object to java

Question

I am building a REST API with a payload that has a property called jsonContent, which holds any valid json.

{
  "name":"foo",
  "jsonContent":{ "abc":"My content"}
}

On the server side I want to map the it to a generic java object ,and eventually save the whole object to mongodb

private String name;
private ?????? jsonContent

I am using jackson for mapping json to java. How do I declare my java object so any json content can be used.

Any json can be represented in terms of maps (String to Object) and lists. I realise it won't work with Jackson, but you could parse the json into a series of maps and lists and then serialize those. — Jason
– Jason, Commented Aug 25, 2016 at 22:52

Amit · Accepted Answer · 2016-08-25 20:42:03Z

1

Use JsonNode:

private JsonNode jsonContent;

answered Aug 25, 2016 at 20:42

Amit

46.5k9 gold badges84 silver badges114 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Sridhar Over a year ago

It works but when the object is saved to mongodb it is deserialized as follows with extra properties and nesting ` {"_class" : "com.fasterxml.jackson.databind.node.ObjectNode", "_children" : { "title" : { "_value" : "Mytitle", "_class" : "com.fasterxml.jackson.databind.node.TextNode" } }, "_nodeFactory" : { "_cfgBigDecimalExact" : false }`

Sridhar · Accepted Answer · 2016-08-26 22:11:36Z

1

I answer my own question, Following worked just fine for me

private Map<String,Object> jsonContent;

answered Aug 26, 2016 at 22:11

Sridhar

1011 silver badge10 bronze badges

Collectives™ on Stack Overflow

Map Dynamic json object to java

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related