Python Float to String TypeError

Question

I am writing a temperature converter for fun and everything seems to be working except I am getting a 'TypeError: Can't convert 'float' object to str implicitly' message. From what I can tell I am converting it to a string after the fact, can anyone tell me what I am doing wrong?

I looked this this question previously "Can't convert 'float' object to str implicitly"

def tempconverter(startType,Temp):
    #conversion types: c -> f c-> K , f -> c, f -> k, k -> c, k -> f
    # maybe have them select only their beginning type then show
    # all temp types by that temperature

if startType[0].lower() == 'c':
    return  ('Your temperature ' + Temp +'\n'
            + 'Farenheight: ' + ((int(Temp)*9)/5)+32 + '\n'
            + 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ##
            )
elif startType[0].lower() == 'f':
    #commented out until first is fixed
    #return  ((int(Temp)-32)*5)/9
    return Temp
elif startType[0].lower() == 'k':
    return  Temp

print('Welcome to our temperature converter program.')
print('''Please enter your temperature type:
         C = Celsius
         F = Farenheight
         K = Kelvin''')
sType = input('> ')

print('Please enter the temperature you wish to convert.')
sTemp = input('> ')

print(tempconverter(sType,sTemp))

You should use %s and %i escapes for your formatting. Looks cleaner and I bet will make your problem easier to trouble shoot if not fix it — Angus
– Angus, Commented Aug 29, 2016 at 21:12
@Angus: I wouldn't recommend that; the %i auto-rounding tends to cause more confusion than it's worth. I'd recommend sticking to the format method, or %s for everything. — user2357112
– user2357112, Commented Aug 29, 2016 at 21:16
I will look into using string formatting, I probably should have been using that but this way seemed less complicated? I dont really have an excuse to not do it. — Taku_
– Taku_, Commented Aug 29, 2016 at 21:19

John Gordon · Accepted Answer · 2016-08-29 21:30:32Z

2

In the line of code:

+ 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ##

The error is caused by this part of it:

Temp+ 273.15

Temp is a string. You can't add a string and a number together.

answered Aug 29, 2016 at 21:30

John Gordon

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1 Comment

Taku_ Over a year ago

I tried int() conversion before and it didnt work.. dammit Oh well Thanks! that fixed it. Now I am going to convert this to string formatting

kindall · Accepted Answer · 2016-08-29 21:12:06Z

1

In this calculation:

((int(Temp)*9)/5)+32

You are not converting your result to str.

Also, you have spelled "Fahrenheit" incorrectly.

answered Aug 29, 2016 at 21:12

kindall

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4 Comments

Taku_ Over a year ago

That isnt the line of code its erroring on? also I know i spelled it wrong.

John Gordon Over a year ago

That isnt the line of code its erroring on Perhaps you'd care to let us know what line of code it is erroring on?

Taku_ Over a year ago

Its in my code above.. + 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ##

John Gordon Over a year ago

Ah, now I see. My bad.

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