php round float number

Question

I have read the documentation and have clear idea of round but i didn't find useful information to solve the problem.

The problem is i have float number which is let say 1.09 and i want to display it 2 instead of 1. if we use round function it display 1. Help me solve this problem.

MORE DETAILS...

$TotalPaidRemaining=1090;
$monthly_installments=1000;
$MakingNumberOfMonths=$TotalPaidRemaining/$monthly_installments;
echo round($MakingNumberOfMonths, 0, PHP_ROUND_HALF_UP);// it display 1. i want it display 2..

What i want is if the value after decimal point is greater than 0. For example 0.01. I want to consider it as 1.

Hope i am clear at my question.

Drown · Accepted Answer · 2016-10-22 18:21:39Z

3

Use the ceil() function instead.

$number = ceil(0.1); // $number will be 1

From the documentation :

Returns the next highest integer value by rounding up value if necessary.

answered Oct 22, 2016 at 18:21

Drown

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Mateusz Palichleb · Accepted Answer · 2016-10-22 18:26:24Z

2

You can use the ceil() php function instead of round(). It will round up your values. Docs: http://php.net/manual/en/function.ceil.php Example: ceil(1.09); // return 2

answered Oct 22, 2016 at 18:26

Mateusz Palichleb

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Comments

Marcelo43 · Accepted Answer · 2016-10-22 18:27:49Z

0

You could use ceil($yourNumber), which will round the number to its next higher integer.

Or you could use round($yourNumber + 0.499999999999999).

Or you could use floor($yourNumber + 1), which rounds the number to its previous highest integer.

answered Oct 22, 2016 at 18:27

Marcelo43

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