How to loop through multiple lines in a python string and convert to integers:

Question

I am attempting to cycle through the following code:

data = "456432 jfhjsdfjs fhdjsjk 990 fdjsf" 345903 fdsfdfs fsfdsfd 667 fsdfd 456432 sfdsfds fdsfdsfd 778 fdsfds"

I want to convert the numbers of the first series of numbers of each line so it returns the following (converted to integers)

Here is the code I have so far, which sorts everything:

print [int(data.split()[0])]

I am guessing I will have to loop through each line while still pulling the 0 item of the list of each line. Though not sure I am on the best workflow for this.

[int(row.split()[0]) for row in data.split('\n')] is one way to do this. — user707650
– user707650, Commented Nov 1, 2016 at 20:49

Francisco · Accepted Answer · 2016-11-01 20:46:38Z

1

You have to iterate line by line, and then do split()[0] to get the first value:

[int(line.split()[0]) for line in data.splitlines()]

answered Nov 1, 2016 at 20:46

Francisco

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2 Comments

FlipTack Over a year ago

oh gosh, I've been on code golf too much, i almost commented saying "-1 byte if you remove the whitespace before for"

Nadim Zaidi Over a year ago

Thanks so much. Worked like a charm!

appills · Accepted Answer · 2016-11-01 20:52:52Z

0

y = [int(x) for x in data.split() if x.isdigit() and int(x) > 99999]
y.sort()

will return a list of ALL numbers in that string as ints that consist of 6 digits

edit: not return, but rather y will be assigned, and then sorted =D so really, y will be a list of all integers in that string which consist of 6 digits

edited Nov 1, 2016 at 20:52

answered Nov 1, 2016 at 20:50

appills

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2 Comments

appills Over a year ago

for d in data.split('\n'):

MooingRawr Over a year ago

OP wants the first number in each string and turned into a number

RomanPerekhrest · Accepted Answer · 2016-11-01 21:13:56Z

0

Another short solution to get the number at the beginning of each line by using re.findall function (from re module) with re.MULTILINE flag:

import re

# your 'data' with text

print(re.findall(r'^\d+\b', data, flags=re.MULTILINE))

The output:

['456432', '345903', '456432']

answered Nov 1, 2016 at 21:13

RomanPerekhrest

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