Reference npm script from npm script

Question

Consider the following example package.json fragment:

{
   // ...
   "scripts": {
       "start": "npm run b -- --watch",
       "build": "builder --in src --out dest"
   }
   // ...
}

In this, I run build from start, and give it an extra flag. The problem with this approach is it actually creates another instance of the NPM run. It works, but it's ugly.

Is there a clean way to reference the build command from the start command without having to make another call to NPM?

RyanZim · Accepted Answer · 2017-01-09 23:23:27Z

1

Is there a clean way to reference the build command from the start command without having to make another call to NPM?

Not really.

If you just don't like npm's verbose output, you can silence that with npm run b -s -- --watch.

If you are calling multiple npm scripts from one parent script, you may want to look into an npm task runner. Here is a list of a few: https://github.com/RyanZim/awesome-npm-scripts#task-runners. (Disclaimer: awesome-npm-scripts is my personal project)

answered Jan 9, 2017 at 23:23

RyanZim

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