Python - Require input from a print function

Question

I am testing a print function, where it looks as if the prompt is typing, defined as type()

I would like to store raw input using the type function:

from time import sleep
import sys
from random import uniform

def type(s):
    for c in s:
    sys.stdout.write('%s' % c)
    sys.stdout.flush()
    sleep(uniform(0, 0.3))

name = raw_input(type("What is your name? "))
type("Hello " + name +"\n")

This is the output of the code:

What is your name? None

Input is still allowed from the user, right after 'None', and the output will be correctly printed, without 'None'. Is there a way to circumvent this?

In this prompt I would like to print everything using the type function.

The problem is that you are passing type() to raw_input. type implicitely returns None, since you did not give it an explicit return value. Perhaps try taking raw_input inside type and returning the result. As an aside, the name type already belongs to the built-in function type, and it is bad practice to shadow it. Choose a different name for your function rather than type. — juanpa.arrivillaga
– juanpa.arrivillaga, Commented Jan 13, 2017 at 6:55
Python already has a function type(). Rename yours to type_() or something else — jkr
– jkr, Commented Jan 13, 2017 at 6:56

PM 2Ring · Accepted Answer · 2017-01-13 06:58:36Z

5

raw_input turns the arg you pass it into a string & uses that as the prompt. You're passing raw_input the return value of your type function, and that function returns the default of None, so that's why "None" gets printed. So just use your function before calling raw_input and call raw_input without an arg.

BTW, you should not use type as a variable or function name because that's the name of a built-in function.

from time import sleep
import sys
from random import uniform

def typer(s):
    for c in s:
        sys.stdout.write('%s' % c)
        sys.stdout.flush()
        sleep(uniform(0, 0.3))

typer("What is your name? ")
name = raw_input()
typer("Hello " + name + "\n")

answered Jan 13, 2017 at 6:58

PM 2Ring

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Comments

Anomitra · Accepted Answer · 2017-01-13 06:57:06Z

1

type("What is your name? ")
name = raw_input()
type("Hello " + name +"\n")

There you go. Any function in Python which has no return statement defined, returns a None by default - which was showing up on your prompt.

answered Jan 13, 2017 at 6:57

Anomitra

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3 Comments

UserASR Over a year ago

name = raw_input("What is your name? ") type("Hello " + name +"\n")

PM 2Ring Over a year ago

@ASR putting multiline Python code into comments is useless because the indentation gets lost.

Julian Johnson Over a year ago

I honestly have no idea why I was trying to complicate this. Thanks for your help. For some reason, I thought that the input would start on a new line.

John F · Accepted Answer · 2017-01-13 06:57:49Z

0

The default return type for a function is None. Thus what is happening is that your type function returns at the end of the function with a None which the raw_input then puts into the stdout stream. Simply having the type function return a blank string would handle the issue:

    return ''

You might want to use a different function name other then type because type is a builtin and can be useful sometimes.

answered Jan 13, 2017 at 6:57

John F

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