Better way to write a polling function in python

Question

I wrote a polling function to check the value of reg_result variable for 120 seconds.

reg_result = 0
while_timeout = time.time() + 120
while reg_result is not "REGISTERED" and time.time() < while_timeout:
    reg_result = LeshanObj.validate_reg_time(parameter_1)

Is there any other better way of writing a polling method?

Is it possible by not using a while loop?

Pauline · Accepted Answer · 2022-12-19 17:25:08Z

14

There is a library in python Polling(https://pypi.python.org/pypi/polling/0.3.0) You can use this

from polling import TimeoutException, poll
try:
    poll(lambda: reg_result=='REGISTERED', timeout=120, step=1)
except TimeoutException as tee:
    print "Value was not registered"

Hope it helps.

edited Dec 19, 2022 at 17:25

Pauline

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answered Jan 18, 2017 at 7:17

Sandeep Hukku

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3 Comments

thagraybush Over a year ago

This prints the Value no matter wether exception is faced or not. It will wait to do the polling but in the end will run the print statement either way.

Tim Dowty Over a year ago

There is now a better alternative: see pypi.org/project/polling2

Geuis Over a year ago

@TimDowty this project is just as broken as the original.

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