How to pick a specific array position in python

Question

What is the right way to match the second position in my array?

my array (d) from HID is [1,1,0,0,0,0,0] or [1,0,0,0,0,0,0]

when position 2 is 1, I want to meet my condition.

This is what I have hacked together:

    while True:
        d = h.read(64)
        if d:
            for btn, val in enumerate(d):
                if btn == 1:
                    if val == 1:
                        print("Condition Finally Met")

Mac · Accepted Answer · 2017-02-08 05:06:55Z

2

Just index directly into the list:

while True:
    d = h.read(64)
    if len(d) >= 2 and d[1] == 1:
        print("Condition Met")

In Python, lists are zero-indexed (i.e. the first item is numbered 0, not 1), so d[1] gets the value of the second item. We also check that the list actually contains at least two items, just in case.

answered Feb 8, 2017 at 5:06

Mac

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