I have situation where I should ignore the timestamp in a date string. I have tried the below command but with no luck.
"start" variable used below is in AbsTime (Ex: 01MAY2017 11:45) and not a string.
start_date = datetime.datetime.strptime(start, '%d%^b%Y').date()
print start_date
My output should be :
01MAY2017 or 01MAY2017 00:00
Could any one help me.
Your directives are slightly off, and you need to capture all the contents (irrespective of what you want to retain).
start_date = datetime.datetime.strptime(start, '%d%b%Y %H:%M').date()
print start_date.strftime('%d%b%Y')
# '01May2017'
Update - Adding complete code below:
import datetime
start = '01MAY2017 11:45'
start_date = datetime.datetime.strptime(start, '%d%b%Y %H:%M').date()
print start_date.strftime('%d%b%Y')
# 01May2017
import datetime instead of from datetime import datetime
datetime twice in the interpreter.
str values (which your question implies), it is your job to tell us what you do have.https://docs.python.org/2/library/datetime.html
To convert the string back to a datetime we can use strptime()
Example using strptime()
datetime.datetime.strptime('10Apr2017 00:00', '%d%b%Y %H:%M')
In [17]: datetime.datetime.strptime('10Apr2017 00:00', '%d%b%Y %H:%M')
Out[17]: datetime.datetime(2017, 4, 10, 0, 0)
Use strftime to form your datetime object
Example using now() returns an datetime object that we form to a string
datetime.datetime.now().strftime('%d%b%Y')
In [14]: datetime.datetime.now().strftime('%d%b%Y')
Out[14]: '10Apr2017'
ValueError: unconverted data remains: 11:45.now() and not OP's format, so this would work.try this
import datetime
start = '01MAY2017 11:45'
start_date = datetime.datetime.strptime(start, '%d%b%Y %H:%M')
print start_date.strftime('%Y-%m-%d')
Actually My Best Option to use the very same datetime object to subtract hours , if you do not wish to use strings and use the datetime Object itself.
Here's an Example:
In [1]: date.strftime('%c')
Out[2]: 'Wed Jul 10 00:00:00 2019'
In [3]: date = datetime.datetime.utcnow()
In [4]: date.strftime('%c')
Out[5]: 'Wed Jul 10 19:06:22 2019'
In [6]: date = date - datetime.timedelta(hours = date.hour, minutes = date.minute, seconds = date.second) #Removing hours, mins,secs
In [7]: date.strftime('%c') #use
Out[8]: 'Wed Jul 10 00:00:00 2019'
start.split()[0]will give you the first output%^bidea from?%&^are on5&6(shift) on the regular keyboard.