Searching Scala array to find a value and mapping it to (Array without the Value,Value)

Question

I have a scala Array of the form :

temp: Array[(Array[String], Long)] 
# Eg.  Array((Array(attr1,1.0,attr2),15),(Array(1.0,attr5),15),(Array(attr3,attr4,0.0),15),(Array(attr3,attr4),5))

I need to take this Array and map it to something like

temp: Array[(Array[String],String, Long)] 
# Eg.  Array((Array(attr1,attr2),1.0,15),(Array(attr5),1.0,15),(Array(attr3,attr4),0.0,15),(Array(attr3,attr4),NULL,15))

I am searching for the string 1.0 and 0.0 and making a new array with 1.0 and 0.0 deleted from the original. Incase 1.0 and 0.0 not present then use NULL as the value. Is there an easy way to do this?

What's the proper procedure if there is more than one "0.0" or "1.0"? — jwvh
– jwvh, Commented Jun 15, 2017 at 21:06
there won't be any duplicates the array has unique values for sure. — Prateek Agrawal
– Prateek Agrawal, Commented Jun 15, 2017 at 21:23

jwvh · Accepted Answer · 2017-06-15 21:21:55Z

1

Change the elements of a collection from one type to another type? Sounds like a map.

temp.map{ case (ss,l) =>
  ( ss.filterNot(_ matches "[01]\\.0")
  , ss.find(_ matches "[01]\\.0").getOrElse("NULL")
  , l )
}  // res0: Array[(Array[String], String, Long)]

answered Jun 15, 2017 at 21:21

jwvh

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4 Comments

Prateek Agrawal Over a year ago

Do I need to import anything I am getting this error: <console>:3: error: illegal start of simple expression

jwvh Over a year ago

No import needed. This code only assumes that a val named temp exists and it is of type Array[(Array[String], Long)].

Prateek Agrawal Over a year ago

I was using () instead of {}. Brilliant. How did you know about the filterNot function. Is there some guide to reach to such cool functions?

jwvh Over a year ago

I keep a tab to the Scala Standard Library open and available at all times. Sometimes I just wander through the pages just to see what new things I can find.

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