What's the cleanest and es6 native (if possible) way to loop through a object array to grab each unique value. Example would like this :
[{
"name" : "joe",
},
,{
"name" : "jean",
},
{
"name" : "joe",
},
{
"name" : "joe",
},
{
"name" : "mike",
}]
and in my results I want to see only : joe, jean, mike (only unique values, no dupes)
Since you mentioned ES6, it seems like a Set object would be what you want since it will do the uniqueness part for you and should do so fairly efficiently:
var objs = [{"name" : "joe"},{"name" : "jean"},{"name" : "joe"},{"name" : "joe"},{"name" : "mike"}];
let uniqueNames = Array.from(new Set(objs.map(item => item.name)));
console.log(uniqueNames);Run this snippet to see the results.
a = [{name:"joe"},{name:"jean"},{name:"joe"},{name:"joe"},{name:"mike"}]
console.log(_.uniq(_.map(a, 'name'))) // Lodash 0.1.0
console.log([...new Set(a.map(o => o.name))]) // ES6<script src="https://cdn.jsdelivr.net/npm/[email protected]/lodash.min.js"></script>
var objs = [{"name" : "joe"},{"name" : "jean"},{"name" : "joe"},{"name" : "joe"},{"name" : "mike"}];
var uniqueNames = objs.map( obj => obj.name )
.filter( (name, idx, arr) => { return arr.indexOf(name) === idx; } );
The .map extracts an array of the name values, and the .filter returns only the unique elements (first instances only).
