How to print source code lines in python logger

Question

Is there some relatively simple way to programmatically include source code lines to python logger report. For example...

import logging

def main():
    something_is_not_right = True
    logging.basicConfig(level=logging.DEBUG,
                        format=('%(filename)s: '    
                                '%(levelname)s: '
                                '%(funcName)s(): '
                                '%(lineno)d:\t'
                                '%(message)s')
                        )

    if something_is_not_right == True:
        logging.debug('some way to get previous line of source code here?')

So that output would look like this.

example.py: DEBUG: main(): 14:       if something_is_not_right == True:

@marcog Sorry for my inability to explain my problem more clearly. TryPyPy and unutbu understood what I was looking for. Hopefully their answers explain what I was after. — ojs
– ojs, Commented Jan 15, 2011 at 9:41
I also made the same assumption as marcog and couldn't understand what the problem was. Perhaps edit your question to read "programmatically include arbitrary source code lines, not just the line that logs" — Captain Lepton
– Captain Lepton, Commented Jun 12, 2013 at 15:24

unutbu · Accepted Answer · 2013-03-19 04:11:18Z

21

import inspect
import logging
import linecache

def main():
    something_is_not_right = True
    logging.basicConfig(level=logging.DEBUG,
                        format=('%(filename)s: '    
                                '%(levelname)s: '
                                '%(funcName)s(): '
                                '%(lineno)d:\t'
                                '%(message)s')
                        )

    if something_is_not_right:
        logging.debug(linecache.getline(
            __file__,
            inspect.getlineno(inspect.currentframe())-1))

if __name__=='__main__':
    main()

yields

test.py: DEBUG: main(): 18:     if something_is_not_right == True:

edited Mar 19, 2013 at 4:11

answered Jan 14, 2011 at 14:03

unutbu

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1 Comment

jarmod Over a year ago

Wow, this is crying out for simple ____file____ and ____line____ (without any of the inspect/currentframe stuff).

TryPyPy · Accepted Answer · 2011-01-14 14:50:32Z

Just because I saw unutbu try something similar, here's the code I came up with (too late to post otherwise):

import logging, sys

# From logging.py
def currentframe():
    """Return the frame object for the caller's stack frame."""
    try:
        raise Exception
    except:
        return sys.exc_traceback

f = open(__file__.rstrip('c'))
owncode = f.readlines()
f.close()

def main():
    something_is_not_right = True
    logging.basicConfig(level=logging.DEBUG,
                        format=('%(filename)s: '
                                '%(levelname)s: '
                                '%(funcName)s(): '
                                '%(lineno)d:\t'
                                '%(message)s')
                        )

    if something_is_not_right == True:
        prev = owncode[currentframe().tb_frame.f_back.f_lineno - 2]
        logging.debug('previous line of source code here:\n%s' % prev)

if __name__ == '__main__':
    main()

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