I have a file.txt which contains lines as:
address1:= ("a010")
address2:= ("b005")
address3:= ("b030")
address4:= ("b008")
address5:= ("a002")
address6:= ("b004")
I need to match only the number followed by "b" as well as its line as:
2: 005
3: 030
4: 008
6: 004
Anybody can help me to do that using python?
Code snippet:
foo = """
address1:= ("a010")
address2:= ("b005")
address3:= ("b030")
address4:= ("b008")
address5:= ("a002")
address6:= ("b004")
"""
import re
pattern = 'address(\d+):= \("b(.*)"\)'
result = re.findall(pattern, foo)
for item in result:
print('{index}: {entry}'.format(index=item[0], entry=item[1]))
Execution Output:
2: 005
3: 030
4: 008
6: 004
Use this expression and capture the group 1:
(?:[b])([0-9]{3})
Here is a sample:
https://regex101.com/r/fL4csm/2
In the case of using python, i suggest you to try to add some code that you coded instead of asking for how to code it. Check this link:
