I have two classes A and B and A is base class of B.
I read that all methods in Python are virtual.
So how do I call a method of the base because when I try to call it, the method of the derived class is called as expected?
>>> class A(object):
def print_it(self):
print 'A'
>>> class B(A):
def print_it(self):
print 'B'
>>> x = B()
>>> x.print_it()
B
>>> x.A ???
Using super:
>>> class A(object):
... def print_it(self):
... print 'A'
...
>>> class B(A):
... def print_it(self):
... print 'B'
...
>>> x = B()
>>> x.print_it() # calls derived class method as expected
B
>>> super(B, x).print_it() # calls base class method
A
Two ways:
>>> A.print_it(x)
'A'
>>> super(B, x).print_it()
'A'
x as the self parameter? I didn't know you could do that...
x as the self parameter. When you use the method on an instantiated object, like x.print_it(), x is automaticaly given as the self parameter. When you use the original function from the class definition (A.print_it), A is not an instantiated object of type A, so it does not give as parameter A and expect a value for the parameter self.Simple answer:
super().print_it()
