Omit object key which has empty string in array

Question

How do I simplify the array below

[ { uuid: '',
    quantity: 3,
    procurement_detail_uuid: '',
    distribution_officer_uuid: '',
    substore_uuid: '2343423443423' },
  { uuid: '',
    quantity: 3,
    procurement_detail_uuid: '',
    distribution_officer_uuid: '',
    substore_uuid: '676767' } ]

to

[ { quantity: 3,
    substore_uuid: '2343423443423' },
  { quantity: 3,
    substore_uuid: '676767' } ]

What is the fastest way reduce and filter those key?

please add a not-so-fast version.

Nina Scholz
– Nina Scholz

2017-11-28 11:03:41 +00:00
Commented Nov 28, 2017 at 11:03 — Nina Scholz
– Nina Scholz, Commented Nov 28, 2017 at 11:03

Ori Drori · Accepted Answer · 2017-11-28 11:10:23Z

1

Map the array, reduce each object's keys, and take only non empty values:

const data = [{"uuid":"","quantity":3,"procurement_detail_uuid":"","distribution_officer_uuid":"","substore_uuid":"2343423443423"},{"uuid":"","quantity":3,"procurement_detail_uuid":"","distribution_officer_uuid":"","substore_uuid":"676767"}];

const result = data.map((o) => Object.keys(o)
  .reduce((r, k) => o[k] !== '' ? Object.assign(r, { [k]: o[k] }) : r, {})
);

console.log(result);

answered Nov 28, 2017 at 11:10

Ori Drori

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Comments

gurvinder372 · Accepted Answer · 2017-11-28 11:10:40Z

1

Use a map followed by forEach and finally delete

arr = arr.map( function(item){ 
   Object.keys( item ).forEach( function(key){ 
      if ( item[key] == '' )
      { 
         delete item[key] 
      } 
    }); 
    return item; 
})

Demo

var arr = [ { uuid: '', quantity: 3, procurement_detail_uuid: '',     distribution_officer_uuid: '', substore_uuid: '2343423443423' },
  { uuid: '',  quantity: 3, procurement_detail_uuid: '',    distribution_officer_uuid: '', substore_uuid: '676767' } ];
  
arr = arr.map( function(item){ Object.keys( item ).forEach( function(key){ if ( item[key] == '' ){ delete item[key] } } ); return item; } )

console.log(arr);

answered Nov 28, 2017 at 11:10

gurvinder372

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