PHP Dynamic Variable With this Keyword

Question

I am trying to generate variable variables in a class method such as:

for ($i=1; $i <= 6; $i++) { 
    echo ${"this->year" . $i . "Season"};
}

I expect to get

$this->year1Season
$this->year2Season

and so on, but instead I get no output.

Note: I have already defined:

private $year1Season;
private $year2Season;

and so on at the top of the class and have defined:

$this->year1Season = $year1Season;
$this->year2Season = $year2Season;

and so on in the constructor.

The code works fine when I use the variables as:

echo $this->year1Season;

but not when I try to generate the variables dynamically.

you can not assign $this->year1Season = $year1Season; It would be better if you show your class code to us — Dhairya Lakhera
– Dhairya Lakhera, Commented Dec 11, 2017 at 5:06

PHPDev · Accepted Answer · 2017-12-11 05:09:51Z

2

For anyone wondering, @marekful 's answer solved my question (the site doesn't let me select comments as answers, but I'd like to give him the props).

His answer is the following:

$this->{'year' . $i .'Season'}

answered Dec 11, 2017 at 5:09

PHPDev

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3 Comments

Himanshu Upadhyay Over a year ago

Its not advised to post answer to your own question.

PHPDev Over a year ago

@HimanshuUpadhyay That's just so that other people can more easily find the answer in case they have the same question.

Dhairya Lakhera Over a year ago

Stackoverflow allow to Question and Post your own answer to help community,

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