Custom ordering multiple strings within a single list in python

Question

data = ['ID:123 GE:m FN:Amir LN:Maleki MN:0400101010 EM:[email protected] ST:VIC',
        'ID:b22 EM:[email protected] ST:VIC GE:F FN:Miniyi LN:Li MN:0430101210 MN:0432101215',
        'ID:153 GE:m FN:John LN:Liu MN:040181010 ST:NSW EM:[email protected]']

I want the following data to be arranged in the order of

key_order = 'ID', 'GE', 'FN', 'LN', 'MN', 'EM', 'ST'

I can do it when there is one string using this code:

data = ['ID:153 GE:m FN:John LN:Liu MN:040181010 ST:NSW EM:[email protected]']
data = data[0].split()
keyorder = ['ID', 'GE','FN','LN','MN','EM', 'ST']
print(sorted(data, key=lambda x: key_order.index(x.split(':')[0]))) 

['ID:153', 'GE:m', 'FN:John', 'LN:Liu', 'MN:040181010', 'EM:[email protected]', 'ST:NSW']

Also having trouble for the final result to be displayed as:

ID:123 GE:m FN:Amir LN:Maleki MN:0400101010 EM:[email protected] ST:VIC
ID:b22 EM:[email protected] ST:VIC GE:F FN:Miniyi LN:Li MN:0430101210 MN:0432101215
ID:153 GE:m FN:John LN:Liu MN:040181010 ST:NSW EM:[email protected]

Thanks heaps

yes sorry i realised that and didnt know how to edit and by that time you posted the answer already haha. too quick — KenjiChan1212
– KenjiChan1212, Commented Jan 20, 2018 at 5:26

DYZ · Accepted Answer · 2018-01-20 05:24:05Z

3

You are very close to the right answer:

def sort_by_key(x):
    return key_order.index(x.split(':')[0])
for d in data:
    print(" ".join(sorted(d.split(), key=sort_by_key)))
#ID:123 GE:m FN:Amir LN:Maleki MN:0400101010 EM:[email protected] ST:VIC
#ID:b22 GE:F FN:Miniyi LN:Li MN:0430101210 MN:0432101215 EM:[email protected] ST:VIC
#ID:153 GE:m FN:John LN:Liu MN:040181010 EM:[email protected] ST:NSW

edited Jan 20, 2018 at 5:24

answered Jan 20, 2018 at 5:16

DYZ

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1 Comment

KenjiChan1212 Over a year ago

omg i struggled with this for weeks and you did it in a few seconds! amazing!! Thank you so much for your help. I really appreciate it

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