Trying to make list 1, into list 2 shown in the code below by removing the brackets and commas within the brackets so I can use the strings for SQLite select queries:
[('Mark Zuckerberg',), ('Bill Gates',), ('Tim Cook',), ('Wlliam Sidis',), ('Elon Musk',)]
['Mark Zuckerberg', 'Bill Gates', 'Tim Cook', 'William Sidis', 'Elon Musk']
While fetching row and storing in list use str(row)
list=[('Mark Zuckerberg',), ('Bill Gates',), ('Tim Cook',), ('Wlliam Sidis',), ('Elon Musk',)]
listoutput=[i[0] for i in list]
print(listoutput)
Check output below
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region=['INDIA','ME',"SEA","AFRICA","SAARC","LATIN AMERICA"]
print region
lst= str(region)
lst.strip("[").strip("]").strip("'")
Suppose you have a list like this one,
animal_raw = [('cat', ), ('dog', ), ('elephant', )]
And now we will convert it into the one you asked that is without commas and parenthesis.
animal = [i[0] for i in animal_raw]
Now , print(animal).
You should now get the output,
['cat', 'dog', 'elephant']
from a tuple we can access the element by index as tuple[index]
single element tuples python represent as
(element,)
you have list of tuples
a = [('Mark Zuckerberg',), ('Bill Gates',), .... ]
b=[]
for i in a :
b.append(i[0])
print(b)
or short version
b = [i[0] for i in a]
[thing[0] for thing in list1]? You have a list of tuples. You're not "removing brackets and comma", you're extracting the first value from the tuple.