I'm getting an error trying to make this
$array = array("text");
echo "text $array['0']";
it's possible to make it shis way instead concatenate
echo "text ".$array['0'];
2 Answers
4 Comments
Nigel Ren
Always disliked the way PHP has these inconsistent ways of doing things.
Niklesh Raut
Nigel Ren
If it's in ", miss out the ', if you miss out the ' when it isn't in " you get a notice (Use of undefined constant) if the index is non-numeric. A few too many if's for me.
Niklesh Raut
you can think about execution and conversion (like interpolation). any language uses the conversion before execution, and php aslo does, it converts
["a"] to [a] but if write [a] it treat as constant and convert with the constant value. so its depends how you write and how it convert before execution. Thanks for comment.1. You need to remove ' around 0
echo "text $array[0]";
Output:- https://eval.in/993458
2.Or enclose array element with {}
echo "text {$array['0']}";
Output:-https://eval.in/993460
answered Apr 24, 2018 at 10:48
Death-is-the-real-truth
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echo "text ".$array['0'];should work{ }-echo "text {$array['0']}";