Execute puppeteer code within a javascript function

Question

Well.., I am new to puppeteer and electron too.

I have a basic puppeteer code working as below :

const puppeteer = require('puppeteer');


(async () => 
{
    const browser = await puppeteer.launch({ headless: false });

    const page = await browser.newPage();
    await page.setViewport({ width: 1366, height: 768});

    await page.goto('https://www.google.co.in', {waitUntil: 'networkidle2'});

})();

That's great. Now i do not wants to open a browser whenever my electron app starts. Rather i want to open it on a particular event and within a javascript function. Which will be called whenever i want. As below :

global.RunCommand = function(param)
{
    const browser = await puppeteer.launch({ headless: false });

    const page = await browser.newPage();
    await page.setViewport({ width: 1366, height: 768});

    await page.goto('https://www.google.co.in', {waitUntil: 'networkidle2'});


    return 'Done : ' + param;
}

which throws :

const browser = await puppeteer.launch({ headless: false });
                    ^^^^^^^^^

SyntaxError: Unexpected identifier
at createScript (vm.js:80:10)
at Object.runInThisContext (vm.js:139:10)
at Module._compile (module.js:606:28)
at Object.Module._extensions..js (module.js:653:10)
at Module.load (module.js:561:32)
at tryModuleLoad (module.js:504:12)
at Function.Module._load (module.js:496:3)

Any help will be appreciated and thanks in advance.

pupeeteer is not an electron project

Vaviloff
– Vaviloff

2018-05-27 13:32:50 +00:00
Commented May 27, 2018 at 13:32 — Vaviloff
– Vaviloff, Commented May 27, 2018 at 13:32

Walter Chapilliquen - wZVanG · Accepted Answer · 2018-05-27 07:34:43Z

3

global.RunCommand is a async function, you must always declare the async word in an asynchronous function

global.RunCommand = async function(param)
{
 ...
}

answered May 27, 2018 at 7:34

Walter Chapilliquen - wZVanG

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2 Comments

sandhya sasane Over a year ago

Yes it worked but i want to return the string 'done' on_complete; But it returning string 'done' before completing code..!!??

NocNit Over a year ago

@sandhyasasane You can use a callback function for that

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