I would like to get values from the array created inside the each loop
var arr = [];
$.each([52, 97], function(index, value) {
var arr = [value];
});
console.log(arr);
But the logged array has no entry.
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1Try use .pus() method to add elemnts to your arrayAbu Machi– Abu Machi2018-06-12 11:44:40 +00:00Commented Jun 12, 2018 at 11:44
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5 Answers
The error what you did is var arr = [ value]; reinitialized variable, test this:
var arr =[];
$.each([ 52, 97 ], function( index, value ) {
arr.push(value);
});
console.log(arr);
Comments
The error what you did is var arr = [ value]; reinitialized variable & wrong setting of array index.
var arr = [];
$.each([52, 97], function(index, value) {
arr[index] = value;
});
console.log(arr);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>You can also do this with push() as in other answer(@Boris Bresciani).
Comments
You can simply use spread syntax to get the array element copied without reference. This means that you can independently change the content of any array without affecting the content of other.
var arr1 = [ 52, 97 ];
var res = [...arr1];
console.log(res);
Comments
Your variable arr inside the function is not the same as the outside variable arr, but local to the function. To fix that, do not create a new local variable, but let the function refer to the outside variable instead (this is called a closure). This should work:
var arr =[];
$.each([ 52, 97 ], function( index, value ) {
arr.push(value);
});
console.log(arr);
Comments
Add value in Array using each loop in js
var ProductTypeId = [];
$("input[name=ProductTypeId]").each(function() {
if ($(this).prop('checked') == true) {
ProductTypeId.push($(this).val());
}
});
alert(ProductTypeId`enter code here`);<input type="checkbox" class="custom-control-input" name="ProductTypeId" id="<?php echo $term['productTypeId']; ?>" value="<?php echo $term['productTypeId']; ?>">
Comments
