NumberFormatException while converting Hexadecimal String to Long

Question

I am trying to convert the following Hexadecimal string cc10000000008401 to Long. Java unexpectedly generating NumberFormatException.

System.out.println(Long.parseLong("cc10000000008401",16));

I think, It should not generate exception as the long representation of the above hexadecimal string is "-3742491290344848383L" which is well inside the range of Long.

Could you please help me to know why I am getting NumberFormatException?

Possible duplicate of How to convert a hexadecimal string to long in java? — user9420984
– user9420984, Commented Aug 2, 2018 at 12:52

Karol Dowbecki · Accepted Answer · 2018-08-02 13:35:06Z

4

cc10000000008401 is 14,704,252,783,364,703,233 which is larger than Long.MAX_VALUE of 9,223,372,036,854,775,807.

Since it overflows long you need to use BigInteger to store it. Since your text values comes as hex you can parse it providing correct radix:

BigInteger i = new BigInteger("cc10000000008401", 16);
System.out.println(i); // 14704252783364703233

edited Aug 2, 2018 at 13:35

answered Aug 2, 2018 at 12:53

Karol Dowbecki

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3 Comments

Tarun Over a year ago

Could you please tell how did you calculate its decimal value. I am getting following decimal value: ‭-3742491290344848383‬

Tarun Over a year ago

I mean, How did you get this value "14,704,252,783,364,703,233".

user85421 Over a year ago

as he commented/answered, by new BigInteger("...", 16) (Note that parseLong expects a - sign for negative numbers)

Mike Samuel · Accepted Answer · 2018-08-02 12:57:48Z

3

In Java8, Long.parseUnsignedLong (javadoc) will handle this.

System.out.println(Long.parseUnsignedLong("cc10000000008401",16));

produces

-3742491290344848383

answered Aug 2, 2018 at 12:57

Mike Samuel

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