5

I have a model called Post which has two fields upvotes and downvotes. Now, upvotes, downvotes are ManyToManyField to a Profile. This is the model:

class Post(models.Model):
    profile = models.ForeignKey(Profile, on_delete=models.CASCADE)
    title = models.CharField(max_length=300)
    content = models.CharField(max_length=1000)
    created_at = models.DateTimeField(auto_now_add=True)
    updated_at = models.DateTimeField(auto_now=True)
    subreddit = models.ForeignKey(Subreddit, on_delete=models.CASCADE)
    upvotes = models.ManyToManyField(Profile, blank=True, related_name='upvoted_posts')
    downvotes = models.ManyToManyField(Profile, blank=True, related_name='downvoted_posts')

So, I want to fetch all the posts such that they are in the order of

total(upvotes) - total(downvotes)

So I have used this query:

Post.objects.annotate(
    total_votes=Count('upvotes')-Count('downvotes')
).order_by('total_votes')

The problem with this query is the total_votes is always turning out to be zero.

The below queries will explain the situation:

In [5]: Post.objects.annotate(up=Count('upvotes')).values('up')
Out[5]: <QuerySet [{'up': 1}, {'up': 3}, {'up': 2}]>

In [6]: Post.objects.annotate(down=Count('downvotes')).values('down')
Out[6]: <QuerySet [{'down': 1}, {'down': 1}, {'down': 1}]>

In [10]: Post.objects.annotate(up=Count('upvotes'), down=Count('downvotes'), total=Count('upvotes')-Count('downvotes')).values('up', 'down', 'total')
Out[10]: <QuerySet [{'up': 1, 'down': 1, 'total': 0}, {'up': 3, 'down': 3, 'total': 0}, {'up': 2, 'down': 2, 'total': 0}]>

Seems like both up and down are having the same value(which is actually the value of up). How can I solve this?

I have tried this:

In [9]: Post.objects.annotate(up=Count('upvotes')).annotate(down=Count('downvotes')).values('up', 'down')
Out[9]: <QuerySet [{'up': 1, 'down': 1}, {'up': 3, 'down': 3}, {'up': 2, 'down': 2}]>

but even this gives the same output.

3
  • Wouldn't it make more sense to have a many-to-many to a profile, and store in the m2m table whether it is an upvote/downvote? Commented Aug 6, 2018 at 6:44
  • Yes, It is a ManyToMany with Profile and I think Django handles that table that you are talking about!! Commented Aug 6, 2018 at 7:21
  • correct, but you can define the through table, and thus add attributes to the relation: docs.djangoproject.com/en/2.1/ref/models/fields/… Commented Aug 6, 2018 at 7:25

2 Answers 2

14

Try to use dictinct argument:

Post.objects.annotate(
    total_votes=Count('upvotes', distinct=True)-Count('downvotes', distinct=True)
).order_by('total_votes')

From the docs:

Combining multiple aggregations with annotate() will yield the wrong results because joins are used instead of subqueries. For most aggregates, there is no way to avoid this problem, however, the Count aggregate has a distinct parameter that may help.

Sign up to request clarification or add additional context in comments.

Comments

0

(I'm aware that this isn't exactly an answer, but code can't be embedded in a comment.)

A better data model would be

class Post:
  # ...

class Vote:
  voter = models.ForeignKey(Profile, on_delete=models.PROTECT)
  post = models.ForeignKey(Post, on_delete=models.CASCADE)
  score = models.IntegerField()  # either -1 or +1; validate accordingly

  class Meta:
    unique_together = [('voter', 'post'),]

This way you could count the current total score for a post simply with

Vote.objects.filter(post=post).aggregate(score=Sum('score'))

However, you should be well aware of the performance implications of doing this (or your original version for that matter) every time. It would be better to add a

score = models.IntegerField(editable=False)

field to the Post, that gets updated with the aggregate score every time a vote is created, modified or deleted.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.