Insert php sql row record into hidden form input value field

Question

I'm trying to insert sql ID record inside php echo form input value. Values that are inserted manualy via input field (by typing) are being displayed fine. Value inside input (named: potnik) is not being displayed. Is it ignored because is inside echo or is inserted wrong?

$sql3 = "
SELECT id, potnik_id, ura, naslov
FROM prevoznik 
ORDER BY HOUR(ura), MINUTE(ura) ASC;
";
$result = $conn->query($sql3);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {

        //Spremenjena oblika datuma
        $date = date_create($row["ura"]);
        $ura_pobiranja = date_format($date,"H:i");
        echo "<div class=\"row list  divider-gray\">
                <div class=\"col-1 fs-09 fw-600\">" . $row["id"] . " </div>
                  <div class=\"col-3 flex-vcenter-items fw-600 fs-09\">" . $row["naslov"] . " </div>
                <div class=\"col-1 flex-vcenter-items fw-600 fs-09\">$ura_pobiranja</div>
            ";

        if ($row["naslov"] !== null) {
            echo " <div class=\"col-6 flex-vcenter-items fs-1\">Nastavi uro<form action='update.php?id=" . $row["id"] . "\"' method='POST'><input name=\"potnik\"  value='".$row["id"]."' type='hidden' /> <input class=\"form-control fancy-border\" type=\"text\" name=\"posodobljeni_cas\"/><input type='submit' value='Posodobi'>  </form></div>";
            echo " </div>";
        }
        else {
            echo " </div>";
        }

    }
} else {
    echo "<div class=\"col flex-vcenter-items fw-100 fs-1\"><i class=\"far fa-frown-open pr-3\"></i>Nimaš še nobenih opravil
                                    </div>";
}

Code that isn't working (hidden input field value):

echo " <form action='update.php?id=" . $row["id"] . "\"' method='POST'><input name=\"potnik\"  value='".$row["id"]."' type='hidden' /> <input class=\"form-control fancy-border\" type=\"text\" name=\"posodobljeni_cas\"/><input type='submit' value='Posodobi'>  </form></div>";

It was a typo, I removed \" and value in the hidden field is still not passing $row["id"] — Slasher
– Slasher, Commented Sep 19, 2018 at 18:37
How do you know that the value is not displayed correctly? Are ou inspecting the element via devtools or what? — Felippe Duarte
– Felippe Duarte, Commented Sep 19, 2018 at 18:40
I inserted custom condition inside update.php to throw me error, That error throws me nothing for that hidden input field and throws me value for manualy entered value at posodobljeni_cas. — Slasher
– Slasher, Commented Sep 19, 2018 at 18:45
@FelippeDuarte Also value "5" is visible if inspecting the element via devtools. — Slasher
– Slasher, Commented Sep 19, 2018 at 18:48

Slasher · Accepted Answer · 2018-09-19 19:05:41Z

1

I had post parameters instead of get parameters set for update.php form action

update.php?id=

echo"Error on update ID:{$_GET['id']} POSODOBLJENI CAS:{$_POST['posodobljeni_cas']}";

answered Sep 19, 2018 at 19:05

Slasher

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