Find regular expression match in string after a given index in Scala

Question

I want to find a match (if any) for a regular expression on a string, but only testing after a given index. For example:

val p = "[a-zA-Z_][a-zA-Z0-9_]*".r
val t = "const pi = 3.141592"
val m = p.findFirstMatchIn(t, start=5) // not real syntax

That is, I want to ignore the first n = 5 characters of the string. Is there any way to do that?

p.findFirstMatchIn(t.drop(5))

jwvh
– jwvh

2018-10-17 17:58:44 +00:00
Commented Oct 17, 2018 at 17:58 — jwvh
– jwvh, Commented Oct 17, 2018 at 17:58

Andrey Tyukin · Accepted Answer · 2018-10-17 15:08:20Z

4

Scala's .r syntax is a thin wrapper around the original java.util.regex.{Pattern, Matcher} API. The original API provides more control. Use Matcher.region:

scala> val m = Pattern.compile("[a-zA-Z_][a-zA-Z0-9_]*").matcher(t)
scala> m.region(5, t.size)
scala> m.find()
scala> m.group(0)
res6: String = pi

answered Oct 17, 2018 at 15:08

Andrey Tyukin

45.1k4 gold badges65 silver badges103 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Find regular expression match in string after a given index in Scala

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related