What are javascript “...array” parameters? [duplicate]

Question

I just started learn Javascript, I'm confused about the function parameter ...[1,2], why the function parameter like this.

function compare(a, b) {
    return a - b;
}
let result = compare(...[1,2]);
console.log(result);

It's called the spread operator. See developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — FThompson
– FThompson, Commented Jan 13, 2019 at 3:18
Although it's worth mentioning that in this particular case it's a poor use, since the function itself won't actually handle more than two arguments. — Paul
– Paul, Commented Jan 13, 2019 at 3:21
It called spread operator. But in this sample code I think we don't need to do this. since your compare function only need two parameters (Assume this is real code). — Hoang Subin
– Hoang Subin, Commented Jan 13, 2019 at 4:25

Nighthawk2730 · Accepted Answer · 2019-01-13 03:29:58Z

1

It's a new Es6 functionality called the spread operator, it's great for calling functions (without apply), converting arguments or NodeList to Arrays, array manipulations, and even when using the Math functions.

https://davidwalsh.name/spread-operator

answered Jan 13, 2019 at 3:29

Nighthawk2730

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