Lodash: How to remove item or nested item from array using an id?

Question

I have an array that looks like the following:

[
    {
        "id": "denuzi",
        "sub":
        [
            {"id": "s4p58o"},
            {"id": "xzbqi"},
        ],
    },
    {
        "id": "4rcodm",
        "sub": [],
    }
]

What I am trying to do is remove an item from the array or from a nested array using a provided id.

e.g. if denuzi is provided then the entire first object is removed; if s4p58o is provided just that object from the first objects sub array is removed.

I know that I can remove an entire object with the following code:

_.remove(this.items, function(item) {
    return item.id !== id;
});

But I am not sure how to make a check to remove a sub item?

Nina Scholz · Accepted Answer · 2019-02-26 12:35:41Z

4

You could take an iterative and recursive approach by checking the id or call again for sub. Exit if found.

function remove(array, id) {
    return array.some((o, i, a) => o.id === id
        ? a.splice(i, 1)
        : remove(o.sub || [], id)
    );
}

var array = [{ id: "denuzi", sub: [{ id: "s4p58o" }, { id: "xzbqi" }] }, { id: "4rcodm", sub: [] }];

remove(array, 's4p58o');
console.log(array);

remove(array, 'denuzi');
console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Feb 26, 2019 at 12:35

Nina Scholz

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Comments

Cristian S. · Accepted Answer · 2019-02-26 12:33:03Z

-3

Just use Array.prototype.filter

var list = [
    {
        "id": "denuzi",
        "sub":
        [
            {"id": "s4p58o"},
            {"id": "xzbqi"},
        ],
    },
    {
        "id": "4rcodm",
        "sub": [],
    }
]

const result = list.filter(a => a.id !== 'denuzi');

console.log(result);

answered Feb 26, 2019 at 12:33

Cristian S.

9735 silver badges13 bronze badges

1 Comment

asifsaho Over a year ago

It doesn't work for nested structure, for example, you s4p58o can't be removed with your solution.

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