I'm stuck trying to figure out the perl regex to extract the following values: (the /home/mail/dump dirs will always be the same). Thanks.
abc
123456
This is the output:
drwxr-xr-x - mail_hd mail_users 0 2011-03-26 20:12 /home/mail/dump/abc
drwxr-xr-x - mail_hd mail_users 0 2011-04-15 09:10 /home/mail/dump/123456
use File::Basename qw( basename ); basename((split(' ', $_, 8))[-1])This is similar to this.
Split on "/" and get the last item
awk -F"/" '{print $NF}' file
Ruby(1.9+) (similar for Perl)
$ ruby -ne 'print $_.sub(/.*\//,"")' file
abc
123456
$ ruby -F"/" -ane 'print $F[-1]' file
abc
123456
The following perl regex will give just the characters after the final forward slash.
s=.*/==
Example:
$ echo 'wxr-xr-x - mail_hd mail_users 0 2011-03-16 18:46 /home/mail/dump/abc' | perl -pe 's=.*/=='
abc
Maybe this is usefull, should return what you need.
if ($subject =~ m!/home/mail/dump/(.*)$!) {
$result = $1;
} else {
$result = "";
}
it matches everything after /home/mail/dump/ until end of line
