I would like to return both the inner and outer array such as the following: [[3],[4],[5]];
This does not work:
var arr = [[1],[2],[3],[4],[5]];
arr.filter(function(el){
return el.filter(function(inner){
return inner >= 3;
});
});
This does not work either:
var arr = [[1],[2],[3],[4],[5]];
arr.map(function(el){
return el.filter(function(inner){
return inner >= 3;
});
});
You can use array destructuring to get easy access to the inner array elements in the callback function:
const array = [[1],[2],[3],[4],[5]];
const filtered = array.filter(([inner]) => inner >= 3);
console.log(array); // original
console.log(filtered); // filtered
map() and filter() functions don't mutate the array, they return a new array with the resulting items.
In the code you show us you're not assigning the result anywhere, also, you're trying to compare an array with a number:
If you wanted to return the values inside of their wrapping arrays, you would do it like this:
var arr = [[1],[2],[3],[4],[5]];
var newArr = arr.filter(function(inner){
return inner[0] >= 3;
});
// newArr = [[3], [4], [5]]
you don't need the map function if you're only filtering.
