Try Except handling with a function in Python

Question

I'm not very well versed in exception handling, and was wondering what happens in a case where the try successfully calls a function, but then there is an error within said function.

try:
    foo()
except:
    ...

def foo():
    ...    # error happens here (no exception handling)

Is the error handled or will we get an error in this case.

For above case, error will be caught from try and the system will run the content inside except — Jessi
– Jessi, Commented Jul 16, 2019 at 19:40
I googled "python exception tutorial" and the very first result covers this (and more!) :) realpython.com/python-exceptions — NPE
– NPE, Commented Jul 16, 2019 at 19:42
Design a little test script (by generating an exception in foo and putting a print statement in the except clause)! You'll go farther faster if you don't rely on others to hand you answers that you can discover for yourself. — unutbu
– unutbu, Commented Jul 16, 2019 at 19:53

Jmonsky · Accepted Answer · 2019-07-16 19:39:33Z

3

The error would be caught by the try outside of the function.

answered Jul 16, 2019 at 19:39

Jmonsky

1,5291 gold badge9 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Zachary Oldham · Accepted Answer · 2019-07-16 19:39:40Z

0

It will fall through to your try-except clause.

answered Jul 16, 2019 at 19:39

Zachary Oldham

8681 gold badge6 silver badges24 bronze badges

Comments

GOVIND DIXIT · Accepted Answer · 2019-07-16 19:41:49Z

0

Try this to catch your error, whenever the specific error occurred the except block code will run:

try:
    foo()
except ErrorName:
   # handle ErrorName exception

answered Jul 16, 2019 at 19:41

GOVIND DIXIT

1,85814 silver badges28 bronze badges

Comments

barker · Accepted Answer · 2019-07-16 19:52:01Z

0

Just to clarify what's going on:

This program fails due to the function being called before defined:

try:
    foo()
except:
    print("failed")
def foo():
    print("my string")

The error is caught in the try, thus printing "failed"

Defining the function prior makes the program work:

def foo():
    print("my string")
try:
    foo()
except:
    print("failed")

answered Jul 16, 2019 at 19:52

barker

1,0551 gold badge20 silver badges37 bronze badges

Collectives™ on Stack Overflow

Try Except handling with a function in Python

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related